Quiz Question #1
Figure 1(a) below shows a drawing of a network \(N\). Figures 1(b), 1(c), and 1(d) shows the matrices \(\boldsymbol A\), \(\boldsymbol D\), \(\boldsymbol S\), respectively, and Figure 1(e) shows the vector \(\boldsymbol{k}\).
Regarding the figures above, consider the following six propositions:
- For matrix \(\boldsymbol A\) (shown in Figure 1(b)) entry \(a_{ij} = 1\) if and only if there is a link in network \(N\) connecting node \(i\) to node \(j\). Therefore, \(\boldsymbol A\) is an adjacency matrix of network \(N\).
- Matrix \(\boldsymbol D\) (shown in Figure 1(c)) can be regarded as a matrix indicating second neighbors (nodes at distance two) of network \(N\), since entry \(d_{ij} \neq \infty\) if and only if nodes \(i\) and \(j\) are second neighbors.
- Matrix \(\boldsymbol D\) (shown in Figure 1(c)) can be regarded as distance matrix of network \(N\) , since if \(d_{ij} = \infty\) there is no path between nodes \(i\) and \(j\), and if \(d_{ij} \neq \infty\), then \(d_{ij}\) equals the length of a shortest path between nodes \(i\) and \(j\).
- Matrix \(\boldsymbol S\) (shown in Figure 1(c)) can be regarded as a matrix of second neighbors of netwok \(N\), since \(s_{ij} =1\) if, and only if, nodes \(i\) and \(j\) are second neighbors.
- Vector \(\boldsymbol{k}\) is the vector of the node degrees of network \(N\) and can be obtained multiplying matrix \(A\) by vector \(\begin{pmatrix}1 & 1 & 1 & 1 & \cdots& 1\end{pmatrix}^T\).
Which alternative contains all TRUE propositions?
(a) 1 and 3.
(b) 1, 2, and 3.
(c) 1, 2, and 5.
(d) 1, 3, 4, and 5.
(e) None of the above.

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